If sum of two numbers equals with sum of two other numbers , then
their product will never be equal . If a+b = c+d ,then ab ≠cd The viceversa is
also true.if ab = cd then a+b ≠c+d.
Let
L and B be the length and breadth of a rectangle. Then its perimeter become
2(L+B) = P and its area A = LB.Another rectangle with same P has
length L’ – (L-a)and breadth B’= (B+a). To have same area A’ = L’B’ =(L-a)(B+a)
= LB +a(L-B) – a2 = LB. Or (L-B) = a which demands L = B+a and B = L-a where the length and
breadth are interchanged..
P =
2L + 2B. and area A = LB.When P remains
same B = (P/2) – L, the ares of the equi-perimeter rectangles A = L[(P/2) – L]
= {PL/2) – L2. .The chnnge in area due to the change in the
dimension of the rectangle having same perimeter dA/dL = (P/2) – 2L A is
maximum when dA/dL = 0 or P = 4L which demands L =B
Let L be the side
of a square. Then its area A = L2 and its perimeter P = 4L. When it
is reshaped into a rectangle with length L’ = L+x and breadth B” = L-x. Then
the area of the rectangle A’ = L’B’ =(L+x)(L-x)= L2 – x2 =
L2 or x = 0..The area of a rectarangle will be maximum when it
becomes a square with same perimeter.