Solve  (a+b)/(a+c) = (a²+b²)/(a²+c²) .Find the whole integer solution for a,b and c.

(a+b) (a²+c²) = (a+c) (a²+b²)

On simplification we have a(c + b) = a² – cb

Give any value to a and find the values of b and c in accordance with the equation.

When a = 8 ; 8(c + b)  = 64 – cb or c = (64-8b)/ (8+b)

If b = 1 ,c = 56/9;  (8 +1)/(8+56/9) = (72 + 9)/(72 +56) = (72² + 9²)/(72² +56²)

If b = 2 ,c = 48/10 = 24/5; (8+2)/(8+24/5) = (40 +2)/(40+24) = (40² +2²)/(40²+24²)

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