Fermat's Last Theorem
Proof.8 General general proof
(M.Meyyappan, Professor of Physics, Sri Raaja Raajan College
Engineering & Technology, Amaravaghipudur-630301-India)
Any power of a number can be expressed as a sum of the number
itself with some multiples of a constant quantity.
a^3 = 6[n(a)]+a for both even and odd numbers
a^4 = 16[n(a)]+1 for odd numbers
= 16[n(a)] for even numbers
a^5= 30 [n(a)]+a for both even and odd numbers
a^6 = 60[n(a)] + a^2 for even numbers
= 240 [n(a)]+ a^2 for odd numbers
a^7= 42[n(a)]+a for both even and odd numbers
a^8 = 16[n(a)]+1 for odd numbers
= 16[n(a)] for even numbers
a^9 = 30 [n(a)]+a for both even and odd numbers
a^10= 60[n(a)]+a^2 for even numbers
=240 [n(a)]+a^2 for odd numbers
Substituting the equivalent for a^n, b^n and c^n in the
supposed relation
a^n+b^n-c^n = 0
where a and b are taken as odd and c is even so that
a,b < c and a+b >c,since all of them cannot be either odd
( because of parity) or even (because reducible).
we find that its resultant equivalent cannot be made to be
equal to zero. If it is zero the supposed relation cannot be
zero. If the supposed relation is zero, the resultant equivalent
cannot be zero.
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